Consider f(x)=sin(x1). Which statement best explains why x→0limf(x) does not exist?
a) The function has a vertical asymptote at x=0, so its values grow without bound as x approaches 0.
b) Because x→0limx1 does not exist, the continuity of the sine function cannot produce a limit for f(x).
c) The function oscillates infinitely often between −1 and 1 as x approaches 0, preventing it from settling on a single value.
d) A limit cannot exist when the function is not defined at the point in question, and f(x) is undefined at x=0.