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Physics
Physics
Problem
Light of frequencies
5.0
×
10
14
Hz
5.0 \times 10^{14}\,\text{Hz}
5.0
×
1
0
14
Hz
and
8.0
×
10
14
Hz
8.0 \times 10^{14}\,\text{Hz}
8.0
×
1
0
14
Hz
produces stopping potentials of
0.5
V
0.5\,\text{V}
0.5
V
and
2.0
V
2.0\,\text{V}
2.0
V
, respectively, for a certain metal. Calculate the value of Planck’s constant (give your answer in J·s to two significant figures).
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