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Mathematics
Mathematics
Problem
Find the limit.
lim
h
→
0
+
h
2
+
6
h
+
19
−
19
h
\lim_{h \to 0^+} \frac{\sqrt{h^2 + 6h + 19} - \sqrt{19}}{h}
h
→
0
+
lim
h
h
2
+
6
h
+
19
−
19
lim
h
→
0
+
h
2
+
6
h
+
19
−
19
h
=
□
\lim_{h \to 0^+} \frac{\sqrt{h^2 + 6h + 19} - \sqrt{19}}{h} = \square
h
→
0
+
lim
h
h
2
+
6
h
+
19
−
19
=
□
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