JEE Advanced 2018 Paper 1 Physics Q17

Physics · Foundations & Measurement

Problem

If the measurement errors in all the independent quantities are known, then it is possible to determine the error in any dependent quantity. This is done by the use of series expansion and truncating the expansion at the first power of the error. For example, consider the relation z = x/y. If the errors in x, y and z are Δx, Δy and Δz, respectively, then z ± Δz = (x/y)(1 ± Δx/x)(1 ± Δy/y)⁻¹. The series expansion for (1 ± Δy/y)⁻¹, to first power in Δy/y, is 1 ∓ (Δy/y). The relative errors in independent variables are always added. So the error in z will be Δz = z(Δx/x + Δy/y). The above derivation makes the assumption that Δx/x ≪ 1, Δy/y ≪ 1. Therefore, the higher powers of these quantities are neglected. If the measurement errors in all the independent quantities are known, then it is possible to determine the error in any dependent quantity. This is done by the use of series expansion and truncating the expansion at the first power of the error. For example, consider the relation z = x/y. If the errors in x, y and z are Δx, Δy and Δz, respectively, then z ± Δz = (x/y)(1 ± Δx/x)(1 ± Δy/y)⁻¹. The series expansion for (1 ± Δy/y)⁻¹, to first power in Δy/y, is 1 ∓ (Δy/y). The relative errors in independent variables are always added. So the error in z will be Δz = z(Δx/x + Δy/y). The above derivation makes the assumption that Δx/x ≪ 1, Δy/y ≪ 1. Therefore, the higher powers of these quantities are neglected. Consider the ratio r = (1 − a)/(1 + a) to be determined by measuring a dimensionless quantity a. If the error in the measurement of a is Δa (Δa/a ≪ 1), then what is the error Δr in determining r?

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