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Problem
Problem
The expression
log
2
5
−
∑
k
=
1
4
log
2
(
sin
(
k
π
5
)
)
\log_2 5 - \sum_{k=1}^{4} \log_2 \left( \sin \left( \frac{k\pi}{5} \right) \right)
lo
g
2
5
−
∑
k
=
1
4
lo
g
2
(
sin
(
5
k
π
)
)
reduces to
p
q
\frac{p}{q}
q
p
, where
p
p
p
and
q
q
q
are co-prime, the value of
p
2
+
q
2
p^2 + q^2
p
2
+
q
2
is a. 13 b. 17 c. 26 d. 29
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