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Mathematics
Mathematics
Problem
The temperature
T
(
t
)
T(t)
T
(
t
)
of a body at time
t
=
0
t = 0
t
=
0
is
160
∘
F
160^\circ F
16
0
∘
F
and it decreases continuously as per the differential equation
d
T
d
t
=
−
K
(
T
−
80
)
\frac{dT}{dt} = -K(T - 80)
d
t
d
T
=
−
K
(
T
−
80
)
, where
K
K
K
is positive constant. If
T
(
15
)
=
120
∘
F
T(15) = 120^\circ F
T
(
15
)
=
12
0
∘
F
, then
T
(
45
)
T(45)
T
(
45
)
is equal to A
85
∘
F
85^\circ F
8
5
∘
F
B
95
∘
F
95^\circ F
9
5
∘
F
C
90
∘
F
90^\circ F
9
0
∘
F
D
80
∘
F
80^\circ F
8
0
∘
F
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