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JEE Advanced 2012 Paper 1 Mathematics Q2
Mathematics
Problem
Let
f
(
x
)
=
{
∣
x
2
∣
∣
cos
π
x
∣
,
x
≠
0
,
0
,
x
=
0
,
f(x)=\begin{cases}|x^2|\left|\cos\dfrac{\pi}{x}\right|,&x\ne0,\\0,&x=0,\end{cases}
f
(
x
)
=
{
∣
x
2
∣
cos
x
π
,
0
,
x
=
0
,
x
=
0
,
x
∈
R
x\in\mathbb R
x
∈
R
, then
f
f
f
is
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