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If
[
2
α
+
1
3
β
0
β
2
−
5
β
]
=
[
α
+
3
β
2
+
2
0
−
6
]
\begin{bmatrix} 2\alpha+1 & 3\beta \\ 0 & \beta^2-5\beta \end{bmatrix} = \begin{bmatrix} \alpha+3 & \beta^2+2 \\ 0 & -6 \end{bmatrix}
[
2
α
+
1
0
3
β
β
2
−
5
β
]
=
[
α
+
3
0
β
2
+
2
−
6
]
…
Problem
If
[
2
α
+
1
3
β
0
β
2
−
5
β
]
=
[
α
+
3
β
2
+
2
0
−
6
]
\begin{bmatrix} 2\alpha+1 & 3\beta \\ 0 & \beta^2-5\beta \end{bmatrix} = \begin{bmatrix} \alpha+3 & \beta^2+2 \\ 0 & -6 \end{bmatrix}
[
2
α
+
1
0
3
β
β
2
−
5
β
]
=
[
α
+
3
0
β
2
+
2
−
6
]
find the equation whose roots are
α
\alpha
α
and
β
\beta
β
.
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