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Problem
Problem
If
a
,
b
∈
[
0
,
π
]
a, b \in [0, \pi]
a
,
b
∈
[
0
,
π
]
and the equation
x
2
+
4
+
3
sin
(
a
x
+
b
)
−
2
x
=
0
x^2 + 4 + 3\sin(ax+b) - 2x = 0
x
2
+
4
+
3
sin
(
a
x
+
b
)
−
2
x
=
0
has atleast one solution, then the value of
(
a
+
b
)
(a+b)
(
a
+
b
)
can be: a.
7
π
2
\frac{7\pi}{2}
2
7
π
b.
3
π
2
\frac{3\pi}{2}
2
3
π
c.
9
π
2
\frac{9\pi}{2}
2
9
π
d. None of these
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