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Mathematics
Mathematics
Problem
The line
3
x
−
4
y
+
12
=
0
3x-4y+12=0
3
x
−
4
y
+
12
=
0
is given. Determine the equation of the line through
(
−
1
,
5
)
(-1,5)
(
−
1
,
5
)
that is perpendicular to this line. a)
4
x
−
3
y
+
19
=
0
4x-3y+19=0
4
x
−
3
y
+
19
=
0
b)
4
x
+
3
y
+
11
=
0
4x+3y+11=0
4
x
+
3
y
+
11
=
0
c)
4
x
+
3
y
−
11
=
0
4x+3y-11=0
4
x
+
3
y
−
11
=
0
d)
3
x
−
4
y
+
23
=
0
3x-4y+23=0
3
x
−
4
y
+
23
=
0
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