Physics

Physics

Problem

A tube of length 0.50 m0.50\,\text{m} is closed at one end. An adjustable tube open at both ends is to be set so that its fundamental frequency equals that of the closed tube. What should be the length of the open tube? (Take v=340 m s−1v = 340\,\text{m\,s}^{-1}.) a) 0.75 m0.75\,\text{m} b) 1.0 m1.0\,\text{m} c) 0.25 m0.25\,\text{m} d) 0.50 m0.50\,\text{m}

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