Mathematics

Mathematics

Problem

If y+x+y−x=c\sqrt{y+x} + \sqrt{y-x} = c , where c≠0c \ne 0 , then dydx\frac{dy}{dx} has the value equal to a. 2xc2\frac{2x}{c^2} b. xy+y2−x2\frac{x}{y + \sqrt{y^2 - x^2}} c. y−y2−x2x\frac{y - \sqrt{y^2 - x^2}}{x} d. c22y\frac{c^2}{2y}

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