Let y(x)=(x2−5x)sinx. Does y satisfy the differential equation dxdy=(2x−5)sinx?
a) Yes; the derivative is (2x−5)sinx exactly.
b) No; differentiating introduces an additional (x2−5x)cosx term.
c) Yes; using the identity sin2x+cos2x=1 shows the extra term vanishes, leaving (2x−5)sinx.},{
d) No; differentiating yields (2x−5)cosx+(x2−5x)sinx, which does not match (2x−5)sinx.