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Mathematics
Problem
The lines
x
−
2
1
=
y
−
3
1
=
z
−
4
−
k
\frac{x-2}{1} = \frac{y-3}{1} = \frac{z-4}{-k}
1
x
−
2
=
1
y
−
3
=
−
k
z
−
4
and
x
−
1
k
=
y
−
4
2
=
z
−
5
1
\frac{x-1}{k} = \frac{y-4}{2} = \frac{z-5}{1}
k
x
−
1
=
2
y
−
4
=
1
z
−
5
are coplanar if a.
k
=
0
k = 0
k
=
0
b.
k
=
−
1
k = -1
k
=
−
1
c.
k
=
2
k = 2
k
=
2
d.
k
=
−
3
k = -3
k
=
−
3
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