Chemistry

Chemistry

Problem

At 298\,K, an elementary reaction has a forward activation energy of 80\,kJ\,mol−1^{-1} and an overall energy change of ΔE=−25 kJ mol−1\Delta E = -25\,\text{kJ}\,\text{mol}^{-1}. What is the activation energy for the reverse reaction? a) 105 kJ mol−1105\,\text{kJ\,mol}^{-1} b) 55 kJ mol−155\,\text{kJ\,mol}^{-1} c) 80 kJ mol−180\,\text{kJ\,mol}^{-1} d) 25 kJ mol−125\,\text{kJ\,mol}^{-1}

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