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Chemistry
Chemistry
Problem
At 298\,K, an elementary reaction has a forward activation energy of 80\,kJ\,mol
−
1
^{-1}
−
1
and an overall energy change of
Δ
E
=
−
25
kJ
mol
−
1
\Delta E = -25\,\text{kJ}\,\text{mol}^{-1}
Δ
E
=
−
25
kJ
mol
−
1
. What is the activation energy for the reverse reaction? a)
105
kJ
mol
−
1
105\,\text{kJ\,mol}^{-1}
105
kJ
mol
−
1
b)
55
kJ
mol
−
1
55\,\text{kJ\,mol}^{-1}
55
kJ
mol
−
1
c)
80
kJ
mol
−
1
80\,\text{kJ\,mol}^{-1}
80
kJ
mol
−
1
d)
25
kJ
mol
−
1
25\,\text{kJ\,mol}^{-1}
25
kJ
mol
−
1
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