Physics

Physics

Problem

The length of metallic wire is ℓ1\ell_1 when tension in it is T1T_1 . It is ℓ2\ell_2 when the tension is T2T_2 . The original length of the wire will be - (a) ℓ1+ℓ22\frac{\ell_1 + \ell_2}{2} (b) T2ℓ1+T1ℓ2T1+T2\frac{T_2 \ell_1 + T_1 \ell_2}{T_1 + T_2} (c) T2ℓ1−T1ℓ2T2−T1\frac{T_2 \ell_1 - T_1 \ell_2}{T_2 - T_1} (d) T1ℓ1−T2ℓ2T2−T1\frac{T_1 \ell_1 - T_2 \ell_2}{T_2 - T_1}

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