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Chemistry
Chemistry
Problem
The potential for the given half-cell at 298 K is (-) ____
×
10
−
2
V
\times 10^{-2}\text{ V}
×
1
0
−
2
V
.
2
H
(
aq
)
+
+
2
e
−
→
H
2
(
g
)
2\text{H}^+_{(\text{aq})} + 2\text{e}^- \rightarrow \text{H}_{2(\text{g})}
2
H
(
aq
)
+
+
2
e
−
→
H
2
(
g
)
[
H
+
]
=
1
M
,
P
H
2
=
2
atm
[\text{H}^+] = 1\text{ M},\; P_{\text{H}_2} = 2\text{ atm}
[
H
+
]
=
1
M
,
P
H
2
=
2
atm
Given:
2.303
RT
/
F
=
0.06
V
2.303\,\text{RT}/\text{F} = 0.06\text{ V}
2.303
RT
/
F
=
0.06
V
,
log
2
=
0.3
\log 2 = 0.3
lo
g
2
=
0.3
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