Physics

Problem

A thin disc of mass

M

and radius

R

has mass per unit area

\sigma(r) = kr^2

where

r

is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is : [Main 10 Apr. 2019 I] a.

\frac{MR^2}{3}

\frac{2MR^2}{3}

\frac{MR^2}{6}

\frac{MR^2}{2}

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