Problem

Problem

The expression (a+b+c)(b+c−a)(c+a−b)(a+b−c)4b2c2\frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4b^2c^2} is equal to a. cos⁡2A\cos^2 A b. sin⁡2A\sin^2 A c. cos⁡Acos⁡Bcos⁡C\cos A \cos B \cos C d. None of these

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