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Mathematics
Mathematics
Problem
If the numerical value of
tan
{
cos
−
1
(
4
5
)
+
tan
−
1
(
2
3
)
}
\tan \left\{ \cos^{-1} \left( \frac{4}{5} \right) + \tan^{-1} \left( \frac{2}{3} \right) \right\}
tan
{
cos
−
1
(
5
4
)
+
tan
−
1
(
3
2
)
}
is
a
b
\frac{a}{b}
b
a
, HCF
(
a
,
b
)
=
1
(a, b) = 1
(
a
,
b
)
=
1
, then a.
a
+
b
=
23
a + b = 23
a
+
b
=
23
b.
a
−
b
=
11
a - b = 11
a
−
b
=
11
c.
3
b
=
a
+
1
3b = a + 1
3
b
=
a
+
1
d.
2
a
=
3
b
2a = 3b
2
a
=
3
b
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