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Mathematics
Mathematics
Problem
For any vectors
a
,
b
\mathbf{a}, \mathbf{b}
a
,
b
,
∣
a
×
b
∣
2
+
(
a
⋅
b
)
2
|\mathbf{a} \times \mathbf{b}|^2 + (\mathbf{a} \cdot \mathbf{b})^2
∣
a
×
b
∣
2
+
(
a
⋅
b
)
2
is equal to a.
∣
a
∣
2
∣
b
∣
2
|\mathbf{a}|^2 |\mathbf{b}|^2
∣
a
∣
2
∣
b
∣
2
b.
∣
a
+
b
∣
|\mathbf{a} + \mathbf{b}|
∣
a
+
b
∣
c.
∣
a
∣
2
−
∣
b
∣
2
|\mathbf{a}|^2 - |\mathbf{b}|^2
∣
a
∣
2
−
∣
b
∣
2
d. 0
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