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Mathematics
Problem
The equation of the curve passing through the origin and satisfying the differential equation
(
1
+
x
2
)
d
y
d
x
+
2
x
y
=
4
x
2
is :
(1 + x^2) \frac{dy}{dx} + 2xy = 4x^2 \text{ is :}
(
1
+
x
2
)
d
x
d
y
+
2
x
y
=
4
x
2
is :
[JEE-Main (On line)-2013] (1)
(
1
+
x
2
)
y
=
x
3
(1 + x^2)y = x^3
(
1
+
x
2
)
y
=
x
3
(2)
3
(
1
+
x
2
)
y
=
4
x
3
3(1 + x^2)y = 4x^3
3
(
1
+
x
2
)
y
=
4
x
3
(3)
3
(
1
+
x
2
)
y
=
2
x
3
3(1 + x^2)y = 2x^3
3
(
1
+
x
2
)
y
=
2
x
3
(4)
(
1
+
x
2
)
y
=
3
x
3
(1 + x^2)y = 3x^3
(
1
+
x
2
)
y
=
3
x
3
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