Problem

Problem

Points D,ED, E are taken on the side BCBC of a triangle ABCABC such that BD=DE=ECBD = DE = EC . If ∠BAD=x\angle BAD = x , ∠DAE=y\angle DAE = y , ∠EAC=z\angle EAC = z , then the value of sin⁡(x+y)sin⁡(y+z)sin⁡xsin⁡z\frac{\sin(x+y) \sin(y+z)}{\sin x \sin z} is equal to a. 1 b. 2 c. 4 d. None of these

Browse the problem library