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Problem 14. If A A A B B B A ⊂ B A \subset B A ⊂ B P ( B ) ≠ 0 P(B) \neq 0 P ( B ) = 0 P ( A ∣ B ) = P ( B ) P ( A ) \mathrm{P}(\mathrm{A} \mid \mathrm{B})=\frac{\mathrm{P}(\mathrm{B})}{\mathrm{P}(\mathrm{A})} P ( A ∣ B ) = P ( A ) P ( B ) P ( A ∣ B ) < P ( A ) \mathrm{P}(\mathrm{A} \mid \mathrm{B})<\mathrm{P}(\mathrm{A}) P ( A ∣ B ) < P ( A ) P ( A ∣ B ) ≥ P ( A ) \mathrm{P}(\mathrm{A} \mid \mathrm{B}) \geq \mathrm{P}(\mathrm{A}) P ( A ∣ B ) ≥ P ( A ) P ( A ∣ B ) = P ( B ) P ( A ) \mathrm{P}(\mathrm{A} \mid \mathrm{B})=\frac{\mathrm{P}(\mathrm{B})}{\mathrm{P}(\mathrm{A})} P ( A ∣ B ) = P ( A ) P ( B ) P ( A ∣ B ) < P ( A ) \mathrm{P}(\mathrm{A} \mid \mathrm{B})<\mathrm{P}(\mathrm{A}) P ( A ∣ B ) < P ( A ) P ( A ∣ B ) ≥ P ( A ) \mathrm{P}(\mathrm{A} \mid \mathrm{B}) \geq \mathrm{P}(\mathrm{A}) P ( A ∣ B ) ≥ P ( A ) Browse the problem library