Linear Algebra Done Right · Problem 5D.15

Inner Product Spaces — Sheldon Axler

Mathematics — Linear Algebra · diagonalizable-operators

Problem

Suppose VV is a finite-dimensional complex vector space, T∈L(V)T \in \mathcal{L}(V), and pp is the minimal polynomial of TT. Prove that the following are equivalent. ((a)) TT is diagonalizable. ((b)) There does not exist λ∈C\lambda \in \mathbf{C} such that pp is a polynomial multiple of (z−λ)2(z - \lambda)^2. ((c)) pp and its derivative p′p' have no zeros in common. ((d)) The greatest common divisor of pp and p′p' is the constant polynomial 11. The greatest common divisor of pp and p′p' is the monic polynomial qq of largest degree such that pp and p′p' are both polynomial multiples of qq. The Euclidean algorithm for polynomials (look it up) can quickly determine the greatest common divisor of two polynomials, without requiring any information about the zeros of the polynomials. Thus the equivalence of (a) and (d) above shows that we can determine whether TT is diagonalizable without knowing anything about the zeros of pp.

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