Chemistry

Problem

Rate constant for

n

th order reaction is given by :

K \cdot t = \frac{1}{(n-1)} [C_A^{1-n} - C_0^{1-n}]

Thus, for a reaction of

n

th order, the ratio of

\frac{t_{1/2}}{t_{3/4}}

is : a.

2^n

2^{n-1}

2^{1-n}

\frac{2^{n-1} - 1}{4^{n-1} - 1}