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Mathematics
Problem
Explain why the function
f
:
R
→
R
f:\mathbb R\to\mathbb R
f
:
R
→
R
defined by
f
(
x
)
=
sin
x
f(x)=\sin x
f
(
x
)
=
sin
x
is not one–one on
R
\mathbb R
R
, but becomes one–one when its domain is restricted to
[
−
π
/
2
,
π
/
2
]
[-\pi/2,\,\pi/2]
[
−
π
/2
,
π
/2
]
.
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