Mathematics

Mathematics

Problem

If a,b,ca, b, c are the sides of 0˘394ABC\u0394 ABC such that 32a2−2⋅3a2+b2+c2+32b2+2c2=03^{2a^2} - 2 \cdot 3^{a^2 + b^2 + c^2} + 3^{2b^2 + 2c^2} = 0 , then Triangle ABCABC is a. equilateral b. right angled c. isosceles right angled d. obtuse angled

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