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Chemistry
Problem Correct order of bond angle is :
a. PH 4 + > OF 2 > SF 2 > SbH 3 > H 2 Te \text{PH}_4^+ > \text{OF}_2 > \text{SF}_2 > \text{SbH}_3 > \text{H}_2\text{Te} PH 4 + > OF 2 > SF 2 > SbH 3 > H 2 Te OF 2 > SF 2 > PH 4 + > SbH 3 > H 2 Te \text{OF}_2 > \text{SF}_2 > \text{PH}_4^+ > \text{SbH}_3 > \text{H}_2\text{Te} OF 2 > SF 2 > PH 4 + > SbH 3 > H 2 Te PH 4 + > SF 2 > OF 2 > SbH 3 > H 2 Te \text{PH}_4^+ > \text{SF}_2 > \text{OF}_2 > \text{SbH}_3 > \text{H}_2\text{Te} PH 4 + > SF 2 > OF 2 > SbH 3 > H 2 Te SF 2 > OF 2 > PH 4 + > SbH 3 > H 2 Te \text{SF}_2 > \text{OF}_2 > \text{PH}_4^+ > \text{SbH}_3 > \text{H}_2\text{Te} SF 2 > OF 2 > PH 4 + > SbH 3 > H 2 Te Browse the problem library