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Mathematics
Mathematics
Problem
For
0
<
A
<
π
2
0 < A < \frac{\pi}{2}
0
<
A
<
2
π
, the value of
log
1
2
(
1
1
+
2
cos
2
A
+
2
sec
2
A
+
2
)
\log_{\frac{1}{2}} \left( \frac{1}{1 + 2 \cos^2 A} + \frac{2}{\sec^2 A + 2} \right)
lo
g
2
1
(
1
+
2
c
o
s
2
A
1
+
s
e
c
2
A
+
2
2
)
is equal to a. 1 b. -1 c. 2 d. 0
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