Problem

Problem

A man of height 2.0 m is standing on a level road where because of temperature variation the refractive index of air is varying as μ=1+ay\mu = \sqrt{1 + ay} , where yy is height from road. If a=2.0×10−6 m−1a = 2.0 \times 10^{-6} \text{ m}^{-1} . Then, find distant point that he can see on the road.

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