Determine whether the series n=1∑∞nsin(n1) converges or diverges.
a) It converges absolutely since for large n, nsin(n1)≤n21, and ∑n21 converges.
b) It converges because n→∞limnsin(n1)=0, so its terms decrease to 0.
c) It diverges because its terms do not approach 0.
d) It converges by the Alternating Series Test because sin(n1) changes sign and decreases in magnitude.