Physics

Problem

On the

x

-axis and at a distance

x

from the origin, the gravitational field due to a mass distribution is given by

\frac{Ax}{(x^2 + a^2)^{3/2}}

in the

x

-direction. The magnitude of gravitational potential on the

x

-axis at a distance

x

, taking its value to be zero at infinity, is : a.

\frac{A}{(x^2 + a^2)^{1/2}}

\frac{A}{(x^2 + a^2)^{3/2}}

A(x^2 + a^2)^{1/2}

A(x^2 + a^2)^{3/2}