Physics

Physics

Problem

The velocity of a motorcycle of mass 250 kg250\,\text{kg} moving along a straight road is given by v=5t1/2v=5 t^{1/2}, where vv is in m s−1\text{m\,s}^{-1} and tt in seconds (t≥0t\ge 0). The motion starts from rest at t=0t=0. a. (i) Derive an expression for the instantaneous power developed by the motorcycle’s engine as a function of time. b. (ii) Calculate the power at t=4 st=4\,\text{s} and at t=9 st=9\,\text{s}. c. (iii) Find the ratio of the two powers obtained in part (ii).

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