Physics

Physics

Problem

In the nuclear chain reaction 92235U⟶56140Ba+3692Kr+301n+E^{235}_{92}\text{U} \longrightarrow ^{140}_{56}\text{Ba} + ^{92}_{36}\text{Kr} + 3 ^{1}_{0}\text{n} + E The number of neutrons given out after three steps is.....

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