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Mathematics
Mathematics
Problem
If
log
(
x
2
+
y
2
)
=
2
tan
−
1
(
y
x
)
\log(x^2 + y^2) = 2 \tan^{-1} \left( \frac{y}{x} \right)
lo
g
(
x
2
+
y
2
)
=
2
tan
−
1
(
x
y
)
, then show that
d
y
d
x
=
x
+
y
x
−
y
\frac{dy}{dx} = \frac{x+y}{x-y}
d
x
d
y
=
x
−
y
x
+
y
.
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