Problem

Problem

For the reaction, 2NO(g)+2H2(g)→N2(g)+2H2O(g)2\text{NO}(\text{g}) + 2\text{H}_2(\text{g}) \rightarrow \text{N}_2(\text{g}) + 2\text{H}_2\text{O}(\text{g}) the rate expression can be written in the following ways: d[N2]dt=k1[NO][H2];d[H2O]dt=k[NO][H2];−d[NO]dt=k1′[NO][H2];−d[H2]dt=k1′′[NO][H2]\begin{aligned} \frac{d[\text{N}_2]}{dt} &= k_1 [\text{NO}][\text{H}_2]; \\ \frac{d[\text{H}_2\text{O}]}{dt} &= k[\text{NO}][\text{H}_2]; \\ -\frac{d[\text{NO}]}{dt} &= k'_1 [\text{NO}][\text{H}_2]; \\ -\frac{d[\text{H}_2]}{dt} &= k''_1 [\text{NO}][\text{H}_2] \end{aligned} The relationship between k,k1,k1′k, k_1, k'_1 and k1′′k''_1 is: (a) k=k1=k1′=k1′′k = k_1 = k'_1 = k''_1 (b) k=2k1=k1′=k1′′k = 2k_1 = k'_1 = k''_1 (c) k=2k1′=k1=k1′′k = 2k'_1 = k_1 = k''_1 (d) k=k1=k1′=2k1′′k = k_1 = k'_1 = 2k''_1

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