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Mathematics
Problem
If
b
n
+
1
=
1
1
−
b
n
b_{n+1} = \frac{1}{1-b_n}
b
n
+
1
=
1
−
b
n
1
for
n
≥
1
n \ge 1
n
≥
1
and
b
1
=
b
3
b_1 = b_3
b
1
=
b
3
then
∑
r
=
1
2001
b
r
2001
\sum_{r=1}^{2001} b_r^{2001}
∑
r
=
1
2001
b
r
2001
is equal to None of these 0 -2001 2001
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