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Mathematics
Problem
The area of the parallelogram inscribed in the ellipse
x
2
a
2
+
y
2
b
2
=
1
\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1
a
2
x
2
+
b
2
y
2
=
1
whose diagonals are the conjugate diameters of the ellipse is given by a.
2
a
b
2ab
2
ab
b.
3
a
b
3ab
3
ab
c.
4
a
b
4ab
4
ab
d.
5
a
b
5ab
5
ab
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