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Mathematics
Mathematics
Problem
Find real values of
θ
\theta
θ
such that
3
+
2
i
sin
θ
1
−
2
i
sin
θ
\frac{3+2i \sin \theta}{1-2i \sin \theta}
1
−
2
i
s
i
n
θ
3
+
2
i
s
i
n
θ
is a real number.
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