Problem

Problem

The axis of a parabola is along the line y=xy = x and the distance of its vertex from origin is 2\sqrt{2} and that from its focus is 222\sqrt{2} . If vertex and focus both lie in the first quadrant, the equation of the parabola is a. (x+y)2=(x−y−2)(x + y)^2 = (x - y - 2) b. (x−y)2=(x+y+2)(x - y)^2 = (x + y + 2) c. (x−y)2=4(x+y−2)(x - y)^2 = 4(x + y - 2) d. (x−y)2=8(x+y−2)(x - y)^2 = 8(x + y - 2)

Browse the problem library