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Mathematics
Mathematics
Problem
Show that
∫
0
π
/
2
d
x
a
2
cos
2
x
+
b
2
sin
2
x
=
π
2
a
b
;
a
,
b
>
0.
\int_{0}^{\pi/2} \frac{dx}{a^2 \cos^2 x + b^2 \sin^2 x} = \frac{\pi}{2ab}; \quad a, b > 0.
∫
0
π
/2
a
2
cos
2
x
+
b
2
sin
2
x
d
x
=
2
ab
π
;
a
,
b
>
0.
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