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Chemistry
Chemistry
Problem
For a gas-phase reaction at
298
K
298\,\text{K}
298
K
,
Δ
G
∘
\Delta G^{\circ}
Δ
G
∘
is measured to be
+
13.3
kJ
⋅
mol
−
1
+13.3\,\text{kJ}\cdot\text{mol}^{-1}
+
13.3
kJ
⋅
mol
−
1
. What is
log
10
K
\log_{10}K
lo
g
10
K
(base-10 logarithm of the equilibrium constant) at this temperature? (
R
=
8.314
J
⋅
mol
−
1
⋅
K
−
1
R = 8.314\,\text{J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}
R
=
8.314
J
⋅
mol
−
1
⋅
K
−
1
) a)
−
5.37
-5.37
−
5.37
b)
2.33
2.33
2.33
c)
−
2.33
-2.33
−
2.33
d)
5.37
5.37
5.37
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