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Problem
Problem
If
α
=
3
sin
−
1
(
6
11
)
\alpha = 3 \sin^{-1} \left( \frac{6}{11} \right)
α
=
3
sin
−
1
(
11
6
)
and
β
=
3
cos
−
1
(
4
9
)
\beta = 3 \cos^{-1} \left( \frac{4}{9} \right)
β
=
3
cos
−
1
(
9
4
)
, where the inverse trigonometric functions take only the principal values, then the correct option(s) is/are [More than one correct option, JEE 2015 Adv.] a.
cos
β
>
0
\cos \beta > 0
cos
β
>
0
b.
sin
β
<
0
\sin \beta < 0
sin
β
<
0
c.
cos
(
α
+
β
)
>
0
\cos(\alpha + \beta) > 0
cos
(
α
+
β
)
>
0
d.
cos
α
<
0
\cos \alpha < 0
cos
α
<
0
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