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Mathematics
Problem
A particle moves along a straight line with velocity
v
(
t
)
=
3
t
2
−
12
t
+
5
v(t)=3t^{2}-12t+5
v
(
t
)
=
3
t
2
−
12
t
+
5
(in m/s), where
t
t
t
is measured in seconds. Determine the particle’s acceleration at
t
=
2
t=2
t
=
2
s.
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