Mathematics

Mathematics

Problem

y=ae−1/x+by = ae^{-1/x} + b is a solution of dydx=yx2\frac{dy}{dx} = \frac{y}{x^2} then (a) a∈R,b=0a \in R, b = 0 (b) a=2,b=1a = 2, b = 1 (c) a=1,b=1a = 1, b = 1 (d) a=2,b=2a = 2, b = 2

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