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Problem Find all solutions of sin 2 x = 3 2 \sin 2x = \dfrac{\sqrt{3}}{2} sin 2 x = 2 3 in the interval 0 ≤ x < 2 π 0 \le x < 2\pi 0 ≤ x < 2 π .
a) { π 6 , 2 π 3 , 7 π 6 , 5 π 3 } \left\{\dfrac{\pi}{6},\;\dfrac{2\pi}{3},\;\dfrac{7\pi}{6},\;\dfrac{5\pi}{3}\right\} { 6 π , 3 2 π , 6 7 π , 3 5 π }
b) { π 12 , 7 π 12 , 13 π 12 , 19 π 12 } \left\{\dfrac{\pi}{12},\;\dfrac{7\pi}{12},\;\dfrac{13\pi}{12},\;\dfrac{19\pi}{12}\right\} { 12 π , 12 7 π , 12 13 π , 12 19 π }
c) { π 6 , π 3 , 7 π 6 , 4 π 3 } \left\{\dfrac{\pi}{6},\;\dfrac{\pi}{3},\;\dfrac{7\pi}{6},\;\dfrac{4\pi}{3}\right\} { 6 π , 3 π , 6 7 π , 3 4 π }
d) { π 6 , 5 π 6 , 7 π 6 , 11 π 6 } \left\{\dfrac{\pi}{6},\;\dfrac{5\pi}{6},\;\dfrac{7\pi}{6},\;\dfrac{11\pi}{6}\right\} { 6 π , 6 5 π , 6 7 π , 6 11 π }
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