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Problem
Problem
For
g
(
x
)
=
sin
(
2
x
−
π
/
4
)
g(x)=\sin(2x-\pi/4)
g
(
x
)
=
sin
(
2
x
−
π
/4
)
, what is the smallest positive value of
x
x
x
in the interval
(
0
,
π
)
(0,\pi)
(
0
,
π
)
for which
g
′
(
x
)
=
0
g'(x)=0
g
′
(
x
)
=
0
? a)
7
π
/
8
7\pi/8
7
π
/8
b)
π
/
4
\pi/4
π
/4
c)
3
π
/
8
3\pi/8
3
π
/8
d)
π
/
8
\pi/8
π
/8
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