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Mathematics
Mathematics
Problem
Compute
lim
x
→
π
/
2
1
−
sin
x
(
x
−
π
2
)
2
\displaystyle \lim_{x \to \pi/2} \dfrac{1 - \sin x}{\bigl(x-\tfrac{\pi}{2}\bigr)^{2}}
x
→
π
/2
lim
(
x
−
2
π
)
2
1
−
sin
x
. a)
1
1
1
b)
−
1
2
-\dfrac{1}{2}
−
2
1
c)
1
2
\dfrac{1}{2}
2
1
d)
0
0
0
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