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Problem
Problem
If
32
tan
8
θ
=
2
cos
2
α
−
3
cos
α
32 \tan^8 \theta = 2 \cos^2 \alpha - 3 \cos \alpha
32
tan
8
θ
=
2
cos
2
α
−
3
cos
α
and
3
cos
2
θ
=
1
3 \cos 2\theta = 1
3
cos
2
θ
=
1
, then find the general value of
α
\alpha
α
.
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